NEET AIPMT SOLVED PAPER SCREENING 2007

  • question_answer
                    The fraction of total volume occupied by the atoms present in a simple cube is:                

    A)                 \[\frac{\pi }{6}\]                              

    B)                 \[\frac{\pi }{3\sqrt{2}}\]               

    C)                 \[\frac{\pi }{4\sqrt{2}}\]               

    D)                 \[\frac{\pi }{4}\]              

    Correct Answer: A

    Solution :

                    For simple cubic                 Radius    \[(r)=\frac{a}{2}\]                 Volume of the atom = \[\frac{4}{3}\pi {{\left( \frac{a}{2} \right)}^{3}}\]                 Packing fraction = \[\frac{\frac{4}{3}\pi {{\left( \frac{a}{2} \right)}^{3}}}{{{a}^{3}}}\]                 \[=\frac{\pi }{6}\]


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