2. Solved Papers
  3. NEET

NEET AIPMT SOLVED PAPER SCREENING 2007

  • question_answer
                    An element, X has the following isotopic composition;                                                                                           \[^{200}X:90%\]                         \[^{199}X:8.0%\]                         \[^{202}X:2.0%\]                 The weighted average atomic mass of the naturally-occurring element X is closest to:

    A)                 200 amu

    B)                 201 amu              

    C)                 202 amu        

    D)                 199 amu

    Correct Answer: A

    Solution :

                           Weight of \[^{200}X=0.90\,\times 200\,=180.00\,amu\]                 Weight of \[^{199}X=0.08\times 199\,=15.92\,amu\]                 Weight of \[^{202}X=0.02\,\times 202\,=4.04\,amu\]                 Total weight \[=199.06\,\times 202\,amu\]


You need to login to perform this action.
You will be redirected in 3 sec spinner