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NEET AIPMT SOLVED PAPER SCREENING 2008

  • question_answer
    A current of 3 A flows through the \[2\Omega \] resistor shown in the circuit. The power dissipated in the \[5\Omega \] resistor is

    A) 4 W

    B)                                        2 W

    C) 1 W                                       

    D) 5 W

    Correct Answer: D

    Solution :

    Key Idea: Voltage across \[2\Omega \]is same as voltage across arm containing \[1\Omega \] and \[5\Omega \] resistances. Voltage across \[2\Omega \] resistance, \[V=2\times 3=6V\] So, voltage across lowest arm, \[{{V}_{1}}=6V\] Current across \[5\Omega ,I=\frac{6}{1+5}=1A\] Thus, power across \[5\Omega ,\] \[P={{I}^{2}}R={{(1)}^{2}}\times 5=5W\]


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