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NEET AIPMT SOLVED PAPER SCREENING 2008

  • question_answer
    If M (A, Z), \[{{M}_{p}}\] and M,, denote the masses of the nucleus \[_{Z}^{A}X,\]proton and neutron respectively       in       units      of \[u(1u=931.5MeV/{{c}^{2}})\] and BE represents its binding energy in MeV, then

    A) \[M(A,Z)=Z{{M}_{p}}+(A-Z){{M}_{n}}-BE/{{c}^{2}}\]

    B) \[M(A,Z)=Z{{M}_{p}}+(A-Z){{M}_{n}}+BE\]

    C) \[M(A,Z)=Z{{M}_{p}}+(A-Z){{M}_{n}}-BE\]

    D) \[M(A,Z)=Z{{M}_{p}}+(A-Z){{M}_{n}}-BE/{{c}^{2}}\]

    Correct Answer: A

    Solution :

    Binding energy of a nucleus containing N neutrons and Z protons is \[BE=[N{{M}_{n}}+Z{{M}_{p}}-M(A,Z)]{{c}^{2}}\] \[\Rightarrow \]\[\frac{BE}{{{c}^{2}}}=N{{M}_{n}}+Z{{M}_{p}}-M(A,Z)\] \[\Rightarrow \]\[\frac{BE}{{{c}^{2}}}=(A-Z){{M}_{n}}+Z{{M}_{p}}-M(A,Z)\] (as N = A - Z) \[\Rightarrow \]\[M(A,Z)=Z{{M}_{p}}+(A-Z){{M}_{n}}-BE/{{c}^{2}}\]


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