A) x
B) \[\frac{383}{283}x\]
C) \[\frac{10}{110}x\]
D) \[\frac{283}{383}x\]
Correct Answer: D
Solution :
Writing ideal gas law \[PV=nRT\]or\[PV=\frac{m}{M}RT\]or\[\frac{PV}{m}=\frac{1}{M}RT\]or\[\frac{P}{\rho }=\frac{RT}{M}\] or\[\frac{\rho }{P}=\frac{1}{T}\] \[\therefore \]\[\frac{{{\rho }_{1}}/{{p}_{1}}}{{{\rho }_{2}}/{{p}_{2}}}=\frac{{{T}_{2}}}{{{T}_{1}}}\]\[\Rightarrow \]\[\frac{x}{({{\rho }_{2}}/{{p}_{2}})}=\frac{383}{283}\] or\[\frac{{{\rho }_{2}}}{{{p}_{2}}}=\frac{283}{383}x\]
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