A) 2 and 4
B) 3 and 5
C) 1 and 4
D) 1 and 5
Correct Answer: C
Solution :
Energy density\[\text{=}\frac{\text{Energy}}{\text{Volume}}\] \[\text{=}\frac{[M{{L}^{2}}{{T}^{-2}}]}{[{{L}^{3}}]}=[M{{L}^{-1}}{{T}^{-2}}]\] Refractive index hole no dimensions. Dielectric constant has no dimensions. Young's modulus, \[Y=\frac{Fl}{A\Delta l}=\frac{[ML{{T}^{-2}}]}{[{{L}^{2}}][L]}=[M{{L}^{-1}}{{T}^{-2}}]\] Magnetic field, \[B=\frac{F}{Il}=\frac{[ML{{T}^{-2}}]}{[A][L]}=[M{{T}^{-2}}{{A}^{-1}}]\] Therefore, option (c) is correct.
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