A) \[\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}/Ad\]
B) \[{{\varepsilon }_{0}}{{E}^{2}}/Ad\]
C) \[{{\varepsilon }_{0}}{{E}^{2}}Ad\]
D) \[\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}Ad\]
Correct Answer: C
Solution :
Energy given by the cell\[E=C{{V}^{2}}\] Here, C = capacitance of condenser \[=\frac{A{{\varepsilon }_{0}}}{d}\] V = potential difference across the plates = Ed Therefore, \[E=\left( \frac{A{{\varepsilon }_{0}}}{d} \right){{(Ed)}^{2}}\] \[=A\,{{\varepsilon }_{0}}{{E}^{2}}d\]
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