A) \[9.0\times {{10}^{-}}^{23}c{{m}^{3}}\]
B) \[6.023\times {{10}^{-}}^{23}c{{m}^{3}}\]
C) \[3.0\times {{10}^{-}}^{23}c{{m}^{3}}\]
D) \[5.5\times {{10}^{-}}^{23}c{{m}^{3}}\]
Correct Answer: C
Solution :
\[6.02\times {{10}^{23}}\]molecules of water = 1 mol = 18 g \[\therefore \]Mass of one molecule of water \[=\frac{18}{6.023\times {{10}^{23}}g}\] \[\because \]\[d=\frac{m}{V}\] \[\therefore \]\[V=\frac{m}{d}=\frac{18}{6.023\times {{10}^{23}}\times 1}\] \[\approx 3\times {{10}^{-23}}c{{m}^{3}}\]
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