A) 0. 6 mole
B) 0.4 mole
C) 7.5 moles
D) 0.2 mole
Correct Answer: A
Solution :
Key Idea:\[3MnO_{4}^{-}+5{{C}_{2}}O_{4}^{2-}+24{{H}^{+}}\xrightarrow[{}]{{}}\] \[3M{{n}^{2+}}+10C{{O}_{2}}+12{{H}_{2}}O\] \[\therefore \]Number of moles of \[MnO_{4}^{-}\]required to oxidise 5 moles of\[{{C}_{2}}O_{4}^{2-}=3\] \[\therefore \]Number of moles of \[MnO_{4}^{-}\]required- to oxidise 1 mole of \[{{C}_{2}}O_{4}^{2-}=\frac{3}{5}\]\[=0.6mol\]
You need to login to perform this action.
You will be redirected in
3 sec
