NEET AIPMT SOLVED PAPER SCREENING 2008

  • question_answer
    The ratio of the radii of gyration of a circular disc to that of a circular ring, each of same mass and radius, around their respective axes is

    A) \[\sqrt{3}:\sqrt{2}\]       

    B)        \[1:\sqrt{2}\]

    C) \[\sqrt{2}:1\]                    

    D) \[\sqrt{2}:\sqrt{3}\]

    Correct Answer: B

    Solution :

    Key Idea: The square root of the ratio of the moment of inertia of a rigid body and its mass is called radius of gyration. As in key idea, radius of gyration is given by \[K=\sqrt{\frac{I}{M}}\]For given problem \[\frac{{{K}_{disc}}}{{{K}_{ring}}}=\sqrt{\frac{{{I}_{disc}}}{{{I}_{ring}}}}\] But \[{{I}_{disc}}\](about its axis) \[=\frac{1}{2}M{{R}^{2}}\] and \[{{I}_{ring}}\] (about its axis) \[=M{{R}^{2}}\]where R is the radius of both bodies. Therefore, Eq. (i) becomes \[\frac{{{K}_{disc}}}{{{K}_{ring}}}=\sqrt{\frac{\frac{1}{2}M{{R}^{2}}}{M{{R}^{2}}}}=1:\sqrt{2}\]


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