A) 4
B) 6
C) 8
D) 2
Correct Answer: A
Solution :
Key Idea: (i) Number of optical isomers \[={{2}^{n}}\]where, n = number of dissimilar asymmetric carbon atoms. (ii) Number of geometrical isomers \[={{2}^{n}}\] where, n = number of double bond only when the two ends of the chain are different \[C{{H}_{3}}CH=CH-C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\overset{*}{\mathop{C}}}\,H-C{{H}_{3}}\] Here, number of optical isomers \[={{2}^{1}}=2\] Number of geometrical isomers \[={{2}^{1}}=2\] Hence, number of stereoisomers = 2 + 2 = 4
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