NEET AIPMT SOLVED PAPER SCREENING 2010

  • question_answer
    The total radiant energy per unit area, normal to the direction of incidence, received at a distance R from the centre of a star of radius r, whose outer surface radiates as a black body at a temperature T K is given by (where \[\sigma \] is Stefan's constant)

    A) \[\sigma {{r}^{2}}{{T}^{4}}/{{R}^{2}}\]                   

    B) \[\sigma {{r}^{2}}{{T}^{4}}/4\pi {{r}^{2}}\]

    C) \[\sigma {{r}^{4}}{{T}^{4}}/{{r}^{4}}\]    

    D)        \[4\pi \,\sigma {{r}^{4}}{{T}^{4}}/{{R}^{2}}\]

    Correct Answer: A

    Solution :

    If r is the radius of the star and T its temperature, then the energy emitted by the star per second through radiation in accordance with Stefan's law will be given by \[A\sigma {{T}^{4}}=4\pi {{r}^{2}}\sigma {{T}^{4}}\]In reaching a distance R this energy will spread over a sphere of radius R; so the intensity of radiation will be given by                                 \[S=\frac{p}{4\pi {{R}^{2}}}=\frac{4\pi {{r}^{2}}\sigma {{T}^{4}}}{4\pi {{R}^{2}}}\]


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