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NEET AIPMT SOLVED PAPER SCREENING 2010

  • question_answer
    A source\[{{\text{S}}_{\text{1}}}\]is producing, \[{{10}^{15}}\] photons/s of wavelength \[5000\overset{\text{o}}{\mathop{\text{A}}}\,\]. Another source \[{{\text{S}}_{\text{2}}}\] is producing\[1.02\times {{10}^{15}}\] photons per second of wavelength \[5100\overset{\text{o}}{\mathop{\text{A}}}\,\]. Then, (power of \[{{\text{S}}_{\text{2}}})/\](power of \[{{\text{S}}_{1}})\] is equal to

    A) 1.00                       

    B)        1.02

    C) 1.04                       

    D)        0.98

    Correct Answer: A

    Solution :

    Number of photons emitted per second \[n=\frac{p}{\left( \frac{hc}{\lambda } \right)}\]                 \[\therefore \]                  \[p=\frac{nhc}{\lambda }\]                 \[\Rightarrow \frac{{{p}_{2}}}{{{p}_{1}}}=\frac{{{n}_{2}}{{\lambda }_{1}}}{{{n}_{1}}{{\lambda }_{2}}}=\frac{1.02\times {{10}^{15}}\times 5000}{{{10}^{15}}\times 5100}=1\]


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