A) (+) Sucrose
B) (+) Lactose
C) (+) Maltose
D) (-) Fructose
Correct Answer: A
Solution :
Key Idea Reducing sugars' that exist in hemiacetal and hemiketal forms, undergo mutarotation in aqueous solution. Among the given carbohydrates, only sucrose is a non-reducing sugar as in it the hemiacetal and hemiketal groups of glucose and fructose are linked together through O-atom and thus, not free. Due to the absence of free hemiacetal or hemiketal group, sucrose does not exhibit mutarotation.
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