A) \[\text{Be}_{\text{2}}^{\text{+}}\]
B) \[\text{Be}_{\text{2}}^{{}}\]
C) \[\text{B}_{\text{2}}^{{}}\]
D) \[\text{Li}_{\text{2}}^{{}}\]
Correct Answer: B
Solution :
Key Idea Molecules with zero bond order, do not exist. \[Be_{2}^{+}(4+4-1=7)=\] \[\sigma 1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,2{{s}^{1}}\] \[BO=\frac{4-3}{2}=0.5\] \[B{{e}_{2}}(4+4=8)=\overset{{}}{\mathop{\sigma }}\,1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\overset{{}}{\mathop{\sigma }}\,2{{s}^{2}},\overset{*}{\mathop{\sigma }}\,2{{s}^{2}}\] \[BO=\frac{4-4}{2}=0\] \[{{B}_{2}}(5+5=10)\] \[=\overset{{}}{\mathop{\sigma }}\,1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\overset{{}}{\mathop{\sigma }}\,2{{s}^{2}},\overset{*}{\mathop{\sigma }}\,2{{s}^{2}},\pi 2p_{x}^{1}\approx \pi 2p_{y}^{1}\] \[BO=\frac{6-4}{2}=1\] \[L{{i}_{2}}(3+3=6)\] \[=\overset{{}}{\mathop{\sigma }}\,1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\sigma 2{{s}^{2}}\] \[BO=\frac{4-2}{2}=1\]Thus, Be; does not exist under normal conditions.
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