A) -89-0 kJ
B) -89.0 J
C) -44.5 kJ
D) -98.0k J
Correct Answer: A
Solution :
We know that, standard Gibbs energy,\[\Delta {{G}^{o}}=-nF{{E}^{o}}_{cell}\] For the cell reaction, \[2A{{g}^{+}}+Cu\xrightarrow[{}]{{}}C{{u}^{2+}}+2Ag\] \[\Delta E_{cell}^{o}=+\,0.46\,\text{V}\] \[\Delta {{G}^{o}}=-2\times 96500\times 0.46\] \[=-88780\,\text{J}\] \[=-88.7\,\text{kJ}\,\text{K}\approx -\text{89}\text{.0}\,\text{kJ}\]
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