A) \[L{{a}^{3+}}(Z=57)\]
B) \[T{{i}^{3+}}(Z=22)\]
C) \[L{{u}^{3+}}(Z=71)\]
D) \[S{{c}^{3+}}(Z=21)\]
Correct Answer: B
Solution :
Key Idea Colour is obtained as a consequence of d-d (or f-f) transition, and for d-d (or f-f) transition, presence of unpaired electrons is the necessary condition. \[L{{a}^{3+}}(Z=57)=[Xe]4{{f}^{o}}5{{d}^{o}}6{{s}^{o}}\] (no unpaired electron) \[T{{i}^{3+}}(Z=22)=[Ar]3{{d}^{1}}4{{s}^{o}}\] (one unpaired electron) \[L{{u}^{3+}}(Z=71)=[Xe]4{{f}^{14}}5{{d}^{o}}6{{s}^{o}}\] (no unpaired electron) \[S{{c}^{3+}}(Z=21)=[Ar]3{{d}^{o}}4{{s}^{o}}\] (no unpaired electron) Hence, only \[T{{i}^{3+}}\]will exhibit colour in aqueous solution.
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