A) -0.372°C
B) -0.520°C
C) + 0.372°C
D) - 0.570° C
Correct Answer: A
Solution :
Depression in freezing point, \[\Delta {{T}_{f}}={{k}_{f}}\times m\] where, m = molality\[=\frac{{{w}_{B}}\times 1000}{{{M}_{B}}\cdot {{W}_{A}}}\] \[=\frac{68.5\times 1000}{342\times 1000}=\frac{68.5}{342}\] \[\Delta {{T}_{f}}=1.86\times \frac{68.5}{342}\] \[=0.372{{\,}^{o}}C\] \[\Delta {{T}_{f}}={{T}^{o}}-{{T}_{s}}\] \[=0-{{0.372}^{o}}C\] \[=-{{0.372}^{o}}C\]
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