A) \[N{{H}_{3}}\]
B) \[{{H}_{2}}O\]
C) \[{{B}_{2}}{{H}_{6}}\]
D) \[C{{H}_{4}}\]
Correct Answer: C
Solution :
Key Idea Electron deficient molecules behave as Lewis acid. Among the given molecules, only diborane is electron deficient, ie, does not have complete octet. Thus, it acts as a Lewis acid. \[\text{N}{{\text{H}}_{\text{3}}}\] and \[{{\text{H}}_{\text{2}}}\text{O}\] being electron rich molecules behave as Lewis base.
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