A) B/2A
B) 2A/B
C) A/B
D) B/A
Correct Answer: B
Solution :
Given, the potential energy of a particle in a force field \[U=\frac{A}{{{r}^{2}}}-\frac{B}{{{r}^{1}}}\] For stable equilibrium, \[F=-\frac{dU}{dr}=0\] \[0=-\frac{2A}{{{r}^{3}}}+\frac{B}{{{r}^{2}}}\]or\[\frac{2A}{r}=B\] The distance of particle from the centre of the field \[r=\frac{2A}{B}\]You need to login to perform this action.
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