A) 0.001
B) 0.01
C) 1
D) 0.05
Correct Answer: A
Solution :
The full scale deflection current \[{{i}_{g}}=\frac{25\,mV}{G}\text{ampere}\] where G is the resistance of the meter. The value of shunt required for converting it into ammeter of range 25 A is \[S=\frac{{{i}_{g}}G}{i-{{i}_{g}}}\] So that,\[S\approx \frac{25\,mV}{25}=0.001\,\Omega \]You need to login to perform this action.
You will be redirected in
3 sec