NEET AIPMT SOLVED PAPER SCREENING 2012

  • question_answer
    A 200 W sodium street lamp emits yellow light of wavelength 0.6 um. Assuming it to be 25% efficient in converting electrical energy to light, the number of photons of yellow light it emits per second is

    A) \[1.5\times {{10}^{20}}\]             

    B)        \[6\times {{10}^{18}}\]                 

    C) \[62\times {{10}^{20}}\]               

    D)        \[3\times {{10}^{19}}\]

    Correct Answer: A

    Solution :

    Efficient power \[p=\frac{N}{\tau }\times \frac{hc}{\lambda }=200\times 0.25\] \[\frac{N}{\tau }=50\times \frac{\lambda }{hc}=1.5\times {{10}^{20}}\]                 \[=\frac{50\times 0.6\times {{10}^{-6}}}{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner