NEET AIPMT SOLVED PAPER SCREENING 2012

  • question_answer
    Acetone is treated with excess of ethanol in the presence of hydrochloric acid. The product obtained is

    A) \[\text{C}{{\text{H}}_{\text{3}}}\text{C}{{\text{H}}_{\text{2}}}\text{C}{{\text{H}}_{\text{2}}}\text{-}\overset{\begin{smallmatrix}  \text{O} \\  \text{ }\!\!|\!\!\text{  }\!\!|\!\!\text{ } \end{smallmatrix}}{\mathop{\text{C}}}\,\text{-C}{{\text{H}}_{\text{3}}}\]

    B) \[\text{C}{{\text{H}}_{\text{3}}}\text{C}{{\text{H}}_{\text{2}}}\text{C}{{\text{H}}_{\text{2}}}\text{-}\overset{\begin{smallmatrix}  \text{O} \\  \text{ }\!\!|\!\!\text{  }\!\!|\!\!\text{ } \end{smallmatrix}}{\mathop{\text{C}}}\,\text{-C}{{\text{H}}_{2}}\text{C}{{\text{H}}_{\text{2}}}\text{C}{{\text{H}}_{\text{3}}}\]

    C)                                    

    D)  

    Correct Answer: D

    Solution :

    When carbonyl compounds are treated with alcohol, they form hemiacetal (henuketal and acetal/ketal.) Note Formadon of hemiketal is a nucleophilic addidon reacdon.


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