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NEET AIPMT SOLVED PAPER SCREENING 2012

  • question_answer
    Limiting molar conductivity of \[\text{N}{{\text{H}}_{\text{4}}}\text{OH}\] \[(i.e.,\,\Delta {{m}_{(N{{H}_{4}}Cl)}})\]is equal to

    A) \[\Delta m(N{{H}_{4}}Cl)+\overset{o}{\mathop{\Delta }}\,m(NaCl)-\overset{o}{\mathop{\Delta }}\,m(NaOH)\]

    B) \[\overset{o}{\mathop{\Delta }}\,m(NaOH)+\overset{o}{\mathop{\Delta }}\,m(NaCl)-\overset{o}{\mathop{\Delta }}\,m(N{{H}_{4}}Cl)\]

    C) \[\overset{o}{\mathop{\Delta }}\,m(N{{H}_{4}}OH)+\overset{o}{\mathop{\Delta }}\,m(N{{H}_{4}}Cl)-\overset{o}{\mathop{\Delta }}\,m(HCl)\]

    D) \[\overset{o}{\mathop{\Delta }}\,m(N{{H}_{4}}OH)+\overset{o}{\mathop{\Delta }}\,m(NaOH)-\overset{o}{\mathop{\Delta }}\,m(NaCl)\]

    Correct Answer: D

    Solution :

    According to Kohlrausch's law, limiting molar conductivity of \[N{{H}_{4}}OH\]


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