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AMU Medical AMU Solved Paper-1995

  • question_answer
    When a body floats in water\[{{\left( \frac{1}{3} \right)}^{rd}}\]of its volume remains outside, whereas\[{{\left( \frac{3}{4} \right)}^{th}}\]of its volume remains outside when it floats in a liquid. The density of the liquid, in gm/cc, is

    A)  8/3               

    B)  4/3

    C)  9/4               

    D)  3/2

    Correct Answer: A

    Solution :

    : Initially, weight of floating body = weight of water displaced \[=volume\text{ }of\text{ }water\times density\times g\] \[=\frac{2V}{3}\times 1\times g=\frac{2Vg}{3}\] In second case, weight of floating body = weight of liquid displaced = volume of liquid\[\times \]density of liquid\[\times g\] \[=\frac{V}{4}dg\] \[\therefore \]\[\frac{Vdg}{4}=\frac{2Vg}{3}\] or \[d=\frac{8}{3}gm/cc\]


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