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AMU Medical AMU Solved Paper-1995

  • question_answer
    Two blocks of masses\[{{m}_{1}}\]and\[{{m}_{2}}\]are lying on a horizontal frictionless table connected by a weightless string as shown in the diagram. The blocks are pulled by a horizontal force F applied to \[{{m}_{1}}\] The common acceleration of the blocks is

    A)  \[F/({{m}_{1}}+{{m}_{2}})\]

    B)  \[F/{{m}_{1}}\]

    C)  \[F/{{m}_{2}}\]

    D)  \[(F+T)/{{m}_{2}}\]

    Correct Answer: A

    Solution :

    : Acceleration\[=\frac{Force}{mass}=\frac{F}{({{m}_{1}}+{{m}_{2}})}\]


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