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AMU Medical AMU Solved Paper-1995

  • question_answer
    In a tank full of water, waves travel a distance of 45 cm in 3 s. If the distance between two consecutive crests is 3 cm, the frequency of the vibrator causing the waves, measured in Hz is

    A)  5                  

    B)  7.5

    C)  3                  

    D)  15

    Correct Answer: A

    Solution :

    : Distance between two consecutive crests\[=\lambda \] \[\therefore \]\[\lambda =3\,cm\] Velocity \[(v)=\frac{distance}{time}=\frac{45}{3}=15\text{ }cm/s\] \[\therefore \]Frequency\[(n)=\frac{v}{\lambda }=\frac{15}{3}=5\,Hz\]


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