A) \[{{d}^{2}},s{{p}^{3}},s{{p}^{3}},\]and\[s{{p}^{2}}\]hybridisation
B) \[s{{p}^{3}}{{d}^{2}},s{{p}^{3}},\]and\[sp\]hybridisation
C) \[{{d}^{2}}s{{p}^{3}}\]or\[s{{p}^{3}}{{d}^{2}},s{{p}^{3}},\]and\[ds{{p}^{2}}\]hybridization
D) \[{{d}^{2}}s{{p}^{3}},s{{p}^{3}},\]and\[s{{p}^{3}}{{d}^{2}}\]hybridization
Correct Answer: C
Solution :
\[{{d}^{2}}s{{p}^{3}}\]or\[s{{p}^{3}}{{d}^{2}},s{{p}^{3}},\]and\[ds{{p}^{2}}\]hybridization
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