(I) |
(II) |
(III) |
(IV) |
A) I
B) II
C) III
D) IV
Correct Answer: A
Solution :
: For photoelectric effect, \[h\upsilon =\phi +\]kinetic energy of electron emitted \[h\upsilon ={{K}_{\max }}\]for maximum kinetic energy or \[\frac{{{K}_{\max }}}{\upsilon }=h=\]slope of the graph. = it is a constant. Frequency\[\upsilon \]of incident light is positive. Hence figure\[(I)\]represents the graph.You need to login to perform this action.
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