A) \[{{10}^{3}}K\]
B) \[{{10}^{5}}K\]
C) \[{{10}^{6}}K\]
D) \[{{10}^{8}}K\]
Correct Answer: B
Solution :
: For hydrogen, mass \[=1.67\times {{10}^{-27}}kg\] specific heat\[=14400\text{ }J/kg\,K\] Change of temperature\[=9\text{ }K\] Energy\[=10.2\text{ }eV=10.2\times 1.6\times {{10}^{-19}}J\] \[\therefore \]Heat energy\[=ms\theta \] or \[10.2\times 1.6\times {{10}^{-19}}\] \[=(1.67\times {{10}^{-27}})\times (14400)\times \theta \] Or \[\theta =\frac{10.2\times 1.6\times {{10}^{-19}}}{1.67\times {{10}^{-27}}\times 14400}K\] or Temperature\[=0.678\times {{10}^{5}}K\] \[\therefore \] Temperature is of the order of\[{{10}^{5}}K\]
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