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AMU Medical AMU Solved Paper-1996

  • question_answer
    A vessel that holds 4.0 g of oxygen at STP will be able to contain the following weight of helium at STP

    A)  4.0 g               

    B)  1.0 g

    C)  0.5 g               

    D)  2.0 g

    Correct Answer: C

    Solution :

     : 32 g of\[{{O}_{2}}\]occupies 22.4 L at STP 4.0 g of\[{{O}_{2}}\]occupies\[\frac{22.4}{32}\times 4\]at STP = 2.8 L at STP 22.4 L volume is occupied by 4 g He 2.8 L volume is occupied by\[\frac{4}{22.4}\times 2.8\] = 0.5 got He.


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