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AMU Medical AMU Solved Paper-1997

  • question_answer
    The binding energy per nucleon for deuteron\[(_{1}^{2}H)\]and helium\[(_{2}^{4}He)\]are 1.1 MeV and 7.0 MeV and 7.0 MeV respectively. The energy released when two deuterons fuse to form a helium nucleus is

    A)  2.2 MeV         

    B)  28 MeV

    C)  23.6 V          

    D)  30.2 MeV

    Correct Answer: C

    Solution :

    : \[2(_{1}^{2}H){{\to }_{2}}H{{e}^{4}}+Q\] (energy) \[\therefore \]\[Q=4\times 7-4\times 1.1\] or \[Q=28-4.4\]      or \[Q=23.6\text{ }Me\text{ }V\].


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