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AMU Medical AMU Solved Paper-1997

  • question_answer
    1.5 g of a substance when dissolved in 60 g water lowered the freezing point by\[0.136{}^\circ C\]. Calculate the molecular weight of the substance when depression constant of water is 1.86.

    A)  329.1             

    B)  439.5

    C)  341.9            

    D)  335.9

    Correct Answer: C

    Solution :

    : According to relation, \[{{M}_{B}}=\frac{1000.{{K}_{f}}{{w}_{B}}}{\Delta {{T}_{f}}.{{w}_{A}}}\] \[{{M}_{B}}\](molar mass of unknown substance) \[=\frac{1000\times 1.86\times 1.5}{0.136\times 60}=341.9\]


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