A) 0.5
B) \[-1\]
C) 2
D) none of the above
Correct Answer: B
Solution :
: While ascending, apparent weight \[=m(g+a)\] \[\therefore \]\[{{W}_{1}}=m(g+a)=m(g+0)\] \[\therefore \]\[{{W}_{1}}=mg\] While descending, \[=m(g-a)\] \[=m(g-0)=mg\] since acceleration is zero. \[\therefore \]\[{{W}_{1}}={{W}_{2}}=mg=\]Lift rises or descends with zero acceleration. Ratio\[\frac{{{W}_{1}}}{{{W}_{2}}}=1\]You need to login to perform this action.
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