AMU Medical AMU Solved Paper-1997

  • question_answer
    If the melting point of ice is\[0{}^\circ C\]and latent heat of fusion is\[5.46\text{ }KJ\text{ }mo{{l}^{-1}},\] the entropy change for the conversion of 18 g of ice to water at 1 atm is

    A)  zero             

    B)  \[20\text{ }J{{K}^{-1}}\]

    C)  \[50\text{ }J{{K}^{-1}}\]           

    D)  \[\text{360 }J{{K}^{-1}}\]

    Correct Answer: B

    Solution :

    : Here, \[\Delta {{H}_{f}}=5.46\text{ }kJ\text{ }mo{{l}^{-1}}\] \[\Delta {{S}_{f}}=\frac{\Delta {{H}_{f}}}{T}=\frac{5.46\times 1000}{273}\text{=20}\,J{{K}^{-1}}\].


You need to login to perform this action.
You will be redirected in 3 sec spinner