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AMU Medical AMU Solved Paper-1998

  • question_answer
    A radio isotope decays of such a rate that after 100 minutes only eight of the original amount remains, the half life of radio isotope is

    A)  31.3 min         

    B)  32.3 min

    C)  33.3 min         

    D)  34.3 min

    Correct Answer: C

    Solution :

    : Decay constant, \[k=\frac{2.303}{t}\log \frac{a}{a-x}\] \[k=\frac{2.303}{t}\log \frac{a}{a/8}\] \[k=\frac{2.303}{100}\log 8\] \[k=0.021\,{{\min }^{-1}}\] \[{{t}_{1/2}}=\frac{0.693}{0.021}=33\,\min \]


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