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AMU Medical AMU Solved Paper-1998

  • question_answer
    An unknown compound A has a molecular formula\[{{C}_{4}}{{H}_{6}},\]when A is treated with an excess of\[B{{r}_{2}},\]a new substance B with formula \[{{C}_{4}}{{H}_{6}}B{{r}_{4}}\]is formed. A forms a white precipitate with ammoniacal silver nitrate solution. A may be

    A)  Butyne-1        

    B)  Butyne - 2

    C)  Butene - 1       

    D)  Butene - 2.

    Correct Answer: A

    Solution :

    : Since A\[({{C}_{4}}{{H}_{6}})\]adds two moles of\[B{{r}_{2}}\]to give B\[({{C}_{4}}{{H}_{6}}B{{r}_{4}})\]therefore, it is a butyne. Further since A forms a white ppt. with ammoniacal\[AgN{{O}_{3}}\] solution therefore, A is 1-butyne. \[C{{H}_{3}}C{{H}_{2}}C\equiv CH+AgN{{O}_{3}}+N{{H}_{4}}OH\xrightarrow[{}]{{}}\]    \[\underset{(white\text{ }ppt.)}{\mathop{C{{H}_{3}}C{{H}_{2}}C}}\,\equiv CAg+N{{H}_{4}}N{{O}_{3}}+{{H}_{2}}O\]


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