• # question_answer A block of mass is suspended from a spring balance. When the block is in air the balance reads 120 N. When it is immersed in water the reading changes to 80 N. The relative density of the material of the block is A)  6 B)  $\frac{6}{2}$ C)  $\frac{6}{3}$ D)  $\frac{6}{4}$

Solution :

: Relative density $=\frac{weight\text{ }of\text{ }body\text{ }in\text{ }air}{weight\text{ }in\text{ }air\text{ }-\text{ }weight\text{ }in\text{ }water}$ $=\frac{120}{120-80}=\frac{120}{40}=\frac{6}{2}$

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