AMU Medical AMU Solved Paper-1999

  • question_answer
    A circular coil of diameter 7cm has 24 turns of wire carrying current of 0.75A. The magnetic moment of the coil is

    A)  \[6.9\times {{10}^{-2}}A{{m}^{2}}\]   

    B)  \[2.3\times {{10}^{-2}}A{{m}^{2}}\]

    C)  \[{{10}^{-2}}A{{m}^{2}}\]        

    D)  \[{{10}^{-3}}A{{m}^{2}}\]

    Correct Answer: A

    Solution :

    : Radius of coil\[=\frac{7}{2}cm=3.5\times {{10}^{-2}}m\] Magnetic moment \[=NIA\] \[\therefore \] \[M=24\times 0.75\times \pi \times {{(3.5\times {{10}^{-2}})}^{2}}\] \[=24\times 0.75\times 3.14\times 3.5\times 3.5\times {{10}^{-4}}\] \[=692.3\times {{10}^{-4}}A{{m}^{2}}\] \[=6.9\times {{10}^{-2}}A{{m}^{2}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner