A) 5.90 BM
B) 8.90 BM
C) 2.8 BM
D) 1.73 BM
Correct Answer: D
Solution :
: For\[M{{n}^{2+}}\]ion in low spin state, number of unpaired electrons = 1. Magnetic moment \[=n\sqrt{n(n+2)}=\sqrt{1\times 3}=1.73\text{ }BM.\]
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