A) \[\Delta H\] and\[\Delta S\]increase and\[T\Delta S>\Delta H\]
B) \[\Delta H\]and\[\Delta S\]decrease and \[\Delta H>T\Delta S\]
C) \[\Delta H\]increases and\[\Delta S\]increases
D) \[\Delta H\]decreases and\[\Delta S\]increases
Correct Answer: C
Solution :
: (i) When\[\Delta H\]and\[\Delta S\]increase, then, if\[T\Delta S>\Delta H\]the reaction is spontaneous. \[\therefore \]\[\Delta G=\Delta H-T\Delta S=-ve\] (ii) When\[\Delta H\]and\[\Delta S\]decrease, then if\[\Delta H>T\Delta S\]. This makes\[\Delta G\]-ve and process is spontaneous. (iii) If,\[\Delta H\]increases and\[\Delta S\]decreases, then \[\Delta G\]is\[+ve\]and process is non-spontaneous. (iv) If\[\Delta H\]decreases and\[\Delta S\]increases, then \[\Delta G=-ve\]and process is spontaneous.
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