A) \[-0.036{}^\circ C\]
B) \[-0.108{}^\circ C\]
C) \[-0.216{}^\circ C\]
D) \[-0.422{}^\circ C\]
Correct Answer: B
Solution :
: Depression in freezing point of 0.01 M aqueous glucose solution\[=0.18{}^\circ C\] Here, \[\Delta {{T}_{f}}={{K}_{f}}\times m\] \[{{K}_{f}}=\frac{0.18}{0.01}=18\] Molality of solution obtained by mixing equal volumes of 0.01 m and 0.002 m solution \[=\frac{0.01+0.002}{2}=\frac{0.012}{2}=0.006m\] For 0.006 m glucose solution, \[\Delta {{T}_{f}}=18\times 0.006=0.108{}^\circ C\].
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