A) 0.184V
B) 0.827V
C) 0.521V
D) 0.490V
Correct Answer: D
Solution :
\[\Delta G=-n\,F{{E}^{o}}\] For, \[C{{u}^{2+}}+2{{e}^{-}}\xrightarrow{{}}Cu\,;\,\Delta G_{1}^{0}=-2\,F(0.337)\]... (i) \[C{{u}^{2+}}+{{e}^{-}}\xrightarrow{{}}C{{u}^{+}}\,;\,\Delta G_{2}^{0}=-\,F(0.153)\] ...(ii) Subtracting (ii) from (i) \[C{{u}^{+}}+{{e}^{-}}\xrightarrow{{}}Cu\] \[\Delta {{G}^{o}}=-0.674\,F+0.153\,F\] \[-nF{{E}^{o}}=-0.521\,F\] \[\because \] For (III) \[n=1,\,\,\therefore \,{{E}^{o}}=0.521\,\,V\].You need to login to perform this action.
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