A) \[0.5\,s\]
B) \[1.0\,s\]
C) \[\sqrt{\frac{2}{3}}\,s\]
D) \[2.0\,s\]
Correct Answer: B
Solution :
Tension in the string \[(T)=m\times g\] \[=30\times 10\] \[=300\,N\] \[T-Mg=Ma\] From the figure \[300-10\times 10a\] \[\Rightarrow \] \[a=20\,\,m{{s}^{-2}}\] Thus, the maximum acceleration with which the stone can be raised is \[a=20\,\,m{{s}^{-2}}\] Given, \[s=10m\] and \[u=0\] \[\therefore \] \[10=\frac{1}{2}(20)\,{{t}^{2}}\]You need to login to perform this action.
You will be redirected in
3 sec