A) Zero
B) \[\frac{GM}{r}\]
C) \[-\frac{2GM}{r}\]
D) \[\frac{-4\,GM}{r}\]
Correct Answer: D
Solution :
Gravitation potential at 0 due to the mass M at \[A,\,\,\,{{V}_{A}}\frac{-GM}{r/2}\] Similarly, for the mass M at B, gravitation potential \[{{V}_{B}}=-\frac{GM}{r/2}\] Total potential \[{{V}_{A}}+{{V}_{B}}=-\frac{GM}{r/2}-\frac{GM}{r/2}\] \[=-\frac{4GM}{r}\]You need to login to perform this action.
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