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AMU Medical AMU Solved Paper-2012

  • question_answer
    A reacts to form P. A plot of the reciprocal of the concentration of A vs time is a straight line. When the initial concentration of A is\[1.0\times {{10}^{-2}}M\], its half-life is found to be 20 min. When initial concentration of A is \[3.0\times {{10}^{-3}}M\] the half-life will be

    A)  20 min                 

    B)  40 min

    C)  56 min                 

    D)  67 min

    Correct Answer: D

    Solution :

                     Since, the plot of the reciprocal of the concentration of A versus time is a straight line. It indicates that the given reaction is of second order. For a second order reaction, \[{{t}_{1/2}}=\frac{1}{ka}\]                 \[20\,\,(\min )=\frac{1}{k\times 1.0\times {{10}^{-2}}M}\]           ... (i)                 \[{{t}_{1/2}}=\frac{1}{k\times 3.0\times {{10}^{-3}}M}\]                                ?. (ii)                 \[\frac{20}{{{t}_{1/2}}}=\frac{1\times 3.0\times {{10}^{-3}}}{1.0\times {{10}^{-2}}\times 1}=66.66\approx 67\,\min \]


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