question_answer

In \[XeO{{F}_{2}}\] molecule, the hybridisation of Xe orbitals is

A)  \[s{{p}^{3}}{{d}^{3}}\]                 

B)  \[s{{p}^{3}}{{d}^{2}}\]

C)  \[s{{p}^{3}}d\]                

D)  \[s{{p}^{3}}\]

Correct Answer: C

Solution :

                 In \[XeO{{F}_{2}}\] molecule \[Xe\] is \[s{{p}^{3}}d\] hybridised. It has 3bp and \[2lp\].