question_answer

The correct order of basic ties of PhNH2 , \[P{{h}_{2}}NH\]and Cyclohexyl- \[N{{H}_{2}}(C)\] is

A)  A > B > C            

B)  A > C > B

C)  C > A > B            

D)  C > B > A

Correct Answer: C

Solution :

                \[C>A>B\]          In diphenylamine, there are two electron withdrawing phenyl groups with -I effect while there is one such group in aniline. Therefore, diphenylamine is a weaker base than aniline which, in turn, is less basic than cyclohexyl amine in which the electron pair on nitrogen can be easily donated to a Lewis acid.