A) 1-propanol
B) 2-propanol
C) propene
D) n-propane
Correct Answer: B
Solution :
(b,d)\[C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}\xrightarrow[NaB{{H}_{4}}]{LiAl{{H}_{4}}}\underset{propan\text{ }-2-ol}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} OH \\ | \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{3}}}}\,\]
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