A) \[{{C}_{6}}{{H}_{5}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,H-{{C}_{6}}{{H}_{5}}\]
B) \[{{H}_{3}}C-OH\]
C) \[{{C}_{6}}{{H}_{5}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{3}}\]
D) \[{{H}_{3}}C-C{{H}_{2}}\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,H-{{C}_{6}}{{H}_{5}}\]
Correct Answer: C
Solution :
The compounds containing \[C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ ||| \end{smallmatrix}}{\mathop{C}}\,-\] and\[C{{H}_{3}}-\overset{\begin{smallmatrix} OH \\ | \end{smallmatrix}}{\mathop{C}}\,H\] groups on heating with (aq)\[NaOH+{{I}_{2}}\] gives iodoform test (yellow ppt of iodoform). Therefore, the compound,\[{{C}_{6}}{{H}_{5}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{3}}\] gives iodoform test.
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